The production of Rotating magnetic field in 3 phase supply is very interesting. When a 3-phase winding is energized from a 3-phase supply, a rotating magnetic field is produced. This field is such that its poles do no remain in a fixed position on the stator but go on shifting their positions around the stator. For this reason, it is called a rotating field. It can be shown that magnitude of this rotating field is constant and is equal to 1.5 fm where fm is the maximumflux due to any phase.

A three phase induction motor consists of three phase winding as its stationary part called stator. The three phase stator winding is connected in star or delta. The three phase windings are displaced from each other by 120°. The windings are supplied by a balanced three phase ac supply.

The three phase currents flow simultaneously through the windings and are displaced from each other by 120° electrical. Each alternating .phase current produces its own flux which is sinusoidal. So all three fluxes are sinusoidal and are separated from each other by 120°. If the phase sequence of the windings is R-Y-B, then mathematical equations for the instantaneous values of the three fluxes Φ

_{R , }Φ_{Y ,}Φ_{B}can be written as,
Φ

_{R }= Φmsin(ωt)
Φ

_{Y }= Φmsin(ωt - 120)
Φ

_{B}_{ }= Φmsin(ωt - 240)
As windings are identical and supply is balanced, the magnitude of each flux is Φm .

### Case 1 : ωt = 0

Φ

_{R }= Φmsin(0) = 0
Φ

_{Y }= Φmsin(0 - 120) = -0.866 Φm
Φ

_{B}_{ }= Φmsin(0 - 240) = +0.866 Φm### Case 2 : ωt = 60

Φ

_{R }= Φmsin(60) = +0.866 Φm
Φ

_{Y }= Φmsin(- 60) = -0.866 Φm
Φ

_{B}_{ }= Φmsin(- 180) = 0### Case 3 : ωt = 120

Φ

_{R }= Φmsin(120) = +0.866 Φm
Φ

_{Y }= Φmsin(0) = 0
Φ

_{B}_{ }= Φmsin(- 120) = -0.866 Φm### Case 4 : ωt = 180

Φ

_{R }= Φmsin(180) = 0
Φ

_{Y }= Φmsin(60) = +.866 Φm
Φ

_{B}_{ }= Φmsin(- 60) = -0.866 Φm
By comparing the electrical and phasor diagrams we can find the the flux rotates one complete 360 degree on the 180 degree displacement of flux.